I remember that question from TBR. It's absolutely ridiculous and will probably never show up on the MCAT.
I generally hang on the sideline when comments like this get posted, but this is one of those times where I want to step in. Your word choice is such that some people may read your post and it's tone, and mistakenly think you are right.
The reality is that this is (a) an altered version of a simple question, (b) a common question, and (c) a question type that is found in the AAMC materials (although they generally have exact numbers for answer choices). The point of this question is to teach a great short cut to those willing to see how easy these things become when you look at them as points on a titration curve. You as a student have the choice to accept and use the tricks or disregard them and do traditional math, but it does a disservice to the forum on the whole when you opt to shoot down a very good technique that works well for many people.
You have a triprotic acid, H
3PO
4 that when treated with a strong base can be converted into three different species. A triprotic curve is really just three separate curves attached equivalence point to starting point. So in this question, you are given 0.1 moles of H
2PO
4- and 0.2 moles HPO
42-. Those species are involved in the
second titration curve, which starts at the first equivalence point and ends at the second equivalence point. If the two species were in equal concentration then pH would equal pK
a2. But, you have more of the conjugate base, so the pH is slightly higher than pK
a2 but not as high as the second equivalence point.
So let's make this question a
number question and see how it goes.
Assuming pK
a1 = 1.8, pK
a2 = 7.2, and pK
a3 =12.0, then what will the pH be when 0.131 moles KH
2PO
4 is mixed with 0.083 moles K
2HPO
4?
a) 1.91
b) 4.64
c) 7.02
d) 7.88
The easiest way to get this within ten seconds or less is to visualize the titration curve and see that you are at a point slightly before the pH = pK
a2, which makes it just less than 7.2. To be safe, you know that the first equivalence point is an average of 1.8 and 7.2 = 4.5, so choice B is way too low. In a few seconds of visualizing you have the best answer without having to write out an equation and do math.
So the point here is that it is a very good question that has a purpose in teaching a method for quickly solving math questions.