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- Jun 20, 2016
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Assuming the COO- group pKA=2; NH2 group pKa=9
@ pH=3>pKa=2 | deprotonated COO-
@pH=3<pKa=9 | protonated NH3+
@pH=7>pKa=2 | deprotonated COO-
@pH=7<pKa=9 | protonated NH3+
@pH=9>pKa=2 | deprotonated COO-
@pH=9=pKa=9 | protonated NH3+ (to balance out - charge on COO-)
or COOH and NH2
Questions:
1. Should I approach this question with more of pH>=<pKa analysis or acidic=protonated; neutral=zwitterion; basic=deprotonated.
2. The key states at pH=3, the COO- group is protonated. On the MCAT, should we just assume that under acidic conditions this will be protonated, what is the cut off mark for that 3-4?
3. If the pH goes to 10, what it look like this:
@pH=10>pKa=2 | deprotonated COO-
@pH=10>pKa=9 | deprotonated ?