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Physic "collisions and energy"

Discussion in 'MCAT Study Question Q&A' started by dorjiako, Aug 14, 2011.

  1. dorjiako

    2+ Year Member

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    Question said: A 10kg block starts from rest at a height of 20m and slides down a frictionless, semicircular track. The block collides with a stationary object of 50kg at the bottom of the track. If the objects stick together upon collision, what is the maximum height that the block-object system could reach? I got the above solution.
    However, follow up question said: In the above question, determine the height reached by each object if the collisin were inelastic and the falling mass rebounded back with a speed of 1m/s?
    I was able to figure out that the height for the rebounded mass (10kg) is 0.051m using v^2 = 2as. s=1/(2x9.8). However, I couldn't the right answer for the height of remaining 50kg object?
    Any help will be greatly appreciated.
     
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  3. FutureDoctor503

    FutureDoctor503 A.W.E.S.O.M.-O
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    You can find the height of 50kg object by using the following equation:

    (m)(g)(h final) = (0.5)(m)(v final)^2 assuming KE is conserved
     
    #2 FutureDoctor503, Aug 14, 2011
    Last edited: Aug 14, 2011
  4. dorjiako

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    I am probably making mistake on the actual value of the final velocity. So, what is the velocity to be used in this problem?
    Thanks.
     
  5. dorjiako

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    Thanks for your help.
     

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