A) static friction is higher because it is a stronger resistance to movement than kinetic. It takes more force to start an object sliding (static) than to keep it sliding (kinetic).
B) It is necessary because you have to know how much the force of gravity is pulling the block down the slope. Static friction will oppose this force to the same amount to prevent moving. However, it should be important to know the mass of the block to know how much force gravity is pulling with (for normal force)
Static friction is the friction of a non-moving object, so it will never be relevant how far the block slid for static friction.
Totally agree on your explanation to A. It's pretty much the way it is, meaning once something breaks free on a uniform surface, it'll keep going.
On B, you might want to rethink the importance of mass. The thing about static friction is that it is a reactionary force, so it varies. When an object lies on a flat surface, there is a normal force cancelling out the weight, so there is no net force. Hence, there is no force due to static friction. As the plane is raised to an increasing angle, the magnitude of the normal force is reduced. In order to remain stationary, the static friction must increase enough to offset the decrease in normal force. This occurs until you reach the maximum possible static friction, mu
s x N.
At the point it's on the verge of breaking free, we have mg sin(theta) = mu
smg cos(theta). The mg cancels out which is why you don't need the mass. The equation reduces to sin (theta) = mu
s cos(theta), so mu
s = sin(theta)/cos(theta).
Conceptually, if you need a steeper angle to get the block to break free, then the maximum frictional force must be larger, which fits with mu
s = sin(theta)/cos(theta). Also, mu
s is unitless, which also fits with the equation.
So in a question you might see something like the following:
Addition of glue to the surface on which the block resides will have what impact on the experiement?
A) It will decrease the threshold angle at which the block breaks free and slides.
B) It will decrease the magnitude of the normal force at all angles above zero.
C) It will increase the value of cos(theta) in the mu
s calculation.
D) It will increase the tan(theta) for the threshold angle at which the block breaks free and slides.