A 5-kg block moving with velocity v approaches a plane which is inclined at 30° to the horizontal and proceeds to slide up the plane. If the plane is 20 meters long, the coefficient of kinetic friction, μk, is , and the block just reaches the top of the plane before coming to a stop, what must be the value of v?
answer is 20 m/s
I tried to use this : mgh -(1/2)mv^2 = ukFn * 20m but it didnt work. I dont understand why this one is not working. -_-
Could you explain this?
This question is on Kaplan subject B 31
Thank you in advance!
answer is 20 m/s
I tried to use this : mgh -(1/2)mv^2 = ukFn * 20m but it didnt work. I dont understand why this one is not working. -_-
Could you explain this?
This question is on Kaplan subject B 31
Thank you in advance!
