Physics Sound, Decibels and distance...

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MCAT guy

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BR has a question: A 50 dB noise is how much further away from its sound source than a 100 dB noise?

Answer: 316 times further away

I understand the difference in intensity is 10^5 but not this concept. BR then refers to an equation that relates I is proportional to 1/r^2 ...

I searched through all my BR equations and then through all of the TPR equations, and I don't see an equation relating the distance of the source to the Intensity. Am I missing something here?
 
Well, the 100dB sound is 100,000x more intense than the 50dB sound, and intensity follows the inverse square law. So if something is twice as far away, it's 1/4 as intense, if it's 8 times further away, it's 1/64 as intense. Working in reverse, if it's 1/100,000 times as intense, it must be sqrt(100,000) times as far away (or 316x).
 
Well, the 100dB sound is 100,000x more intense than the 50dB sound, and intensity follows the inverse square law. So if something is twice as far away, it's 1/4 as intense, if it's 8 times further away, it's 1/64 as intense. Working in reverse, if it's 1/100,000 times as intense, it must be sqrt(100,000) times as far away (or 316x).

thx bro.

So I guess it is I = power/area
 
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