This is only in the context of orgo. You can have optically active, non-polar, octahedral complexes (I'm not sure about all at once though). Consider the various conformers of SBr2Cl2F2. There exists pair of enantiomers for this compound. And there are non-polar conformers.
Bruh can we be best friends since you just touched on my favorite topic in chemistry.
Answer is no though, mate. Consider the ternary interhalogen, IBrF2 - specifically - the conformer with the axial F-I-F configuration. This has some symmetry. Is it non-polar? No.
That's right, bruh 😉. I drew that shizz bruh. It's symmetrical. Think of all the forces acting on the the iodines. They're identical. So you can actually fold the axial F-I-F bond in half (fold as to put F on top of F) and you'll find that the molecule's various parts lines up perfectly.
Keep in mind what optically active means. For the purposes of the MCAT, optically active compounds are those that are chiral and not meso. So, as @Teleologist mentioned, a compound such as HF, while polar, is not optically active b/c it has no chirality.
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