16.What is the identity of the precipitate that forms in the experiment?
A. BaSO4
A is the best answer. This question tests your memorization skills, but can also be solved quickly using charges. We first must determine the charges of the individual species making up our two aqueous reactants, barium hydroxide and sulfuric acid. We know that the charge on Ba must be 2+, since it is combined with two hydroxide ions (which always have a 1- charge) to form barium hydroxide. The charge on SO4 is 2-, since two hydrogen ions (which always have a 1+ charge) combine with the sulfate ion to form sulfuric acid. Therefore, barium and sulfate combine in a 1:1 ratio. The best answer is A.
B. Ba2SO4
C. BaHSO4
D. Ba(HSO4)
Are precipates usually identified by their charges? If the charges equally cancel out in a solubility problem would they be considered to fall out of the solution? Just some background...the solution contained H2SO4 and BA(OH)2 was added until BaSO4 was precipated out.
A. BaSO4
A is the best answer. This question tests your memorization skills, but can also be solved quickly using charges. We first must determine the charges of the individual species making up our two aqueous reactants, barium hydroxide and sulfuric acid. We know that the charge on Ba must be 2+, since it is combined with two hydroxide ions (which always have a 1- charge) to form barium hydroxide. The charge on SO4 is 2-, since two hydrogen ions (which always have a 1+ charge) combine with the sulfate ion to form sulfuric acid. Therefore, barium and sulfate combine in a 1:1 ratio. The best answer is A.
B. Ba2SO4
C. BaHSO4
D. Ba(HSO4)
Are precipates usually identified by their charges? If the charges equally cancel out in a solubility problem would they be considered to fall out of the solution? Just some background...the solution contained H2SO4 and BA(OH)2 was added until BaSO4 was precipated out.