this is a binomial distribution.
so first you need to find how many possible arrangements of 4's you get get out 5 tries. That's equal to 5C2 which will be 10. So there are 10 possible ways with order not counting to get two 4's in five throws. Next we multiply by the probability of it happening (1/6) and by the probability of it NOT happening (5/6).
The general formula is nCr x (p^r) x (q^n-r) where p is it happening and q is it NOT happening.
So we have 10 x (1/6)^2 x (5/6)^3 = 10*125/6^5 which is the answer
😀 and i like the puppy too