Proton NMR of (P) Xylene

[bugmenotlol]

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I went through achiever and it say there are two singlets in this nmr.


In case you didn't know, there are two methyl group para to each other on a benzene.

I am guessing since the H of the aromatic is equivalent*all four of them, there is no splitting because there is no nonequivalent. Nonequivalent only split. Is this correct?

 

[Decan]

I believe so...

 

[rimmies]

you are correct. If they are symmetrical then they will not split. but, it's also going to be half of what you would expect with splitting.