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proton velocity in magnetic field

Discussion in 'MCAT Study Question Q&A' started by ssiding, Dec 18, 2008.

  1. ssiding

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    Traveling at an initial speed of 1.5 e 6 m/s, a proton enters a region of constant magnetic field of magnitue 1.5T. It the proton's initial velocity vector makes an angle of 30 degrees with the magnetic field, compute the proton's speed 4 seconds after entering th emagnetic field.

    A. 5 e 5 m/s
    B. 7.5 e 5 m/s
    C. 1.5 e 6 m/s
    D. 3.0 e 6 m/s
     
  2. soby10

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    The answer is c 1.5 X 10^6 m/s. The same as the initial velocity b/c at a constatnt B field the velocity is constant. This is due to def. of magnetic filed B=F/q(v*sine angle). Force is perpendicular to both velocity and B field. Since force is always perpendicular to veolcity it does no work. W=Force *distance*(cos 90) so it changes direction but never changes magnitude of velocity. Hope that explains it.
     
  3. isaacmn

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    when charges move in a constant magnetic field ..it undergoes a uniformed circular motion in the form of centripetal fore with constant velocity

    qvbsintheta= v2/r
     

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