g3k SDN Donor 10+ Year Member 5+ Year Member 15+ Year Member Sep 7, 2004 #1 Advertisement - Members don't see this ad I know I am appearing dumb. Can someone help me with solution equlibria in GC?.. I want to know how do we relate the concentration of the two ions of a solute in a solution? In Kaplan it says [OH]- = 3[Fe]3+... I do not understand. Thank u G3K
Advertisement - Members don't see this ad I know I am appearing dumb. Can someone help me with solution equlibria in GC?.. I want to know how do we relate the concentration of the two ions of a solute in a solution? In Kaplan it says [OH]- = 3[Fe]3+... I do not understand. Thank u G3K
L Lilith Senior Member 7+ Year Member 15+ Year Member 20+ Year Member Sep 8, 2004 #2 Fe(OH)3 ---> Fe3+ + 3 (OH)- So for dissociation of every mole of Iron (III) hydroxide, one mole of Fe3+, and 3 moles of OH- ions are formed. Therefore [Fe3+] = 3[OH-]. Upvote 0 Downvote
Fe(OH)3 ---> Fe3+ + 3 (OH)- So for dissociation of every mole of Iron (III) hydroxide, one mole of Fe3+, and 3 moles of OH- ions are formed. Therefore [Fe3+] = 3[OH-].
g3k SDN Donor 10+ Year Member 5+ Year Member 15+ Year Member Sep 8, 2004 #3 Lilith said: Fe(OH)3 ---> Fe3+ + 3 (OH)- So for dissociation of every mole of Iron (III) hydroxide, one mole of Fe3+, and 3 moles of OH- ions are formed. Therefore [Fe3+] = 3[OH-]. Click to expand... Thank u Upvote 0 Downvote
Lilith said: Fe(OH)3 ---> Fe3+ + 3 (OH)- So for dissociation of every mole of Iron (III) hydroxide, one mole of Fe3+, and 3 moles of OH- ions are formed. Therefore [Fe3+] = 3[OH-]. Click to expand... Thank u
