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[anschutz1913]

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Hello,

First of all, I am new to this board and want to thank everyone for being so helpful.

I am taking my DAT on the 22nd, and in preparation, cannot figure out this math problem;

18. What is the probability of randomly selecting three of the four aces in a row without replacement from a deck of 52 cards? A. 1:50,000
B. 1:180,000
C. 1:500
D. 1:1180
E. 1:132,600



Any help would be appreciated.



Thanks,
ANZ

 

[dentrilla]

I would think that the answer is 1:5525(not an option lol), where'd you get this question from?

 

[cmills66]

i totally agree with dentrilla:

the probability of selecting the first ace is (4/52 = 1/13)
the probability of selecting the second ace is (3/51 = 1/17)
the probability of selecting the third ace is (2/50 = 1/25)

multiply each (1/13)(1/17)(1/25) = 1/5525

...somebody correct me if i am wrong

 

[anschutz1913]

I got this from AcetheDAT. I have noticed a lot of problems with their answers just being flat out wrong. So I did the similar math as posted above, but thought I might have been doing something.

What are your experiences with ACETHEDAT. I personally think it sucks, and glad it was pretty inexpensive. I cant believe that it was actually recommended to me by several smart individuals.

ANZ

 

[athlete19]

it is undoubtedly 1/5525. don't know how they messed that up. haha