QR question - ADA 2009

[belmont3]

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Determine the sets of points whose distances from (-2,2) and (3,-3) are in the ratio of 2:3.

a) Circle with center (-3,3) with radius 2 square root of 6.
b) Circle with center (-6,6) with radius 6 square root of 2.
c) Ellipse with equation (X^2 +9) + ( Y^2 +36) = 1
d) Ellipse with equation (x^2 + 36) + ( Y^2 + 9) = 1
e) Ellipse with semiaxes x = square root of 3, Y = square root of 6.

The answer is choice B. I solved this problem using the distance between 2 points. However, it took long time to solve it. I was wondering if any of you Pre-dents have an easier way to solve this problem with less time?!!??! Thanks!

 

[TheEpicFruitCake]

You post a ton of questions lol. It's good to ask questions but not until you've given effort to find the answer.
http://lmgtfy.com/?q=Determine the sets of points whose distances from (-2,2) and (3,-3) are in the ratio of 2:3.
The first link has the explanation. Also the second one has the exact same question asked on sdn.

 

[belmont3]

You post a ton of questions lol. It's good to ask questions but not until you've given effort to find the answer.
http://lmgtfy.com/?q=Determine the sets of points whose distances from (-2,2) and (3,-3) are in the ratio of 2:3.
The first link has the explanation. Also the second one has the exact same question asked on sdn.

Lol, I know. But it's always good to share ideas with others 🙂
I actually googled this question before typing it here. But I didn't understand the other method, lol. I thought someone here will actually have a better explanation.