QR question - DAT

[belmont3]

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I don't have the answer sheet with me and I can't figure out how to solve this question. I attached the question with this thread.

Here are the answer choices.

a) 8/3
b) 14/3
c) 18/3
d) 20/3
e) 46/ 3

Thank you!

 

[KyoPhan]

Edit: Fixed slope

Slope is -3/2 or 3/2. Figure out the distance x-wise it takes to get from the bottom to the top. That's 10 * (2/3). The distance to go from bottom to top, and to to bottom again is just 2* [10 * (2/3)]. So the final distance is just
the starting position 2+ 2(x-distance from bottom to top)
2+2* [10 * (2/3)] = 46/3.

 

[belmont3]

Slope is -2/3 or 2/3. Figure out the distance x-wise it takes to get from the bottom to the top. That's 10 * (2/3). The distance to go from bottom to top, and to to bottom again is just 2* [10 * (2/3)]. So the final distance is just
the starting position 2+ 2(x-distance from bottom to top)
2+2* [10 * (2/3)] = 46/3.

Okay, I think there is something wrong with your solution since the correct answer is B not E.

Also, the slope should be the difference in the Y values over the difference in the X values not the opposite. The only thing I can't understand is how did you know that the distance from bottom to top is 10 times the slope??! What equation/ formula did you use for that?

 

[KyoPhan]

You are correct, the slope is y/x and I messed up. However, that still shouldn't change my answer, so someone else should probably help until I figure out what I did wrong.

For the x-distance, I didn't really use a formula. All I did was ask myself the following:
The distance from bottom to top is 10. For every instance(or jump), I can travel 3 in the y-direction and 2 in the x. How many instances are required( or how many times do I have to jump) to reach the top of the square? So that gets me 10/3 jumps.

Then to figure out how far x-wise I went, I just took the amount of jumps * the amount I travel in the x-direction for each jump. Perhaps it's hard to follow, but that's how my brain thinks.
That gets me 10/3 * 2 = 20/3

Edit: Grammar/further clarification

 

[KyoPhan]

Oh, the box only goes 10 units in the x-direction as well. So we have to figure how far it goes backwards.

It travels 46/3 in the x-direction total. The box x-length is 10, and our distance traveled is more than 10. We have to figure out how far towards the left it will travel after it hits the right side of the box.

So subtract 10 units from distance traveled, that gives us 46/3 - 30/3 = 16/3

It hits the right side of the box, and travels 16/3 more towards the left.

Final position:
(30/3)-(16/3) =14/3

The 30/3 comes from the x-position at the very right of the box. The length of the box is 10 after all.

 

[FancyFloss]

You won't see anything like this on the DAT.