QR question for yall

Started by dexadental
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dexadental

dexadental

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Hey guys...I have a QR question for yall. Kaplan writes this stuff thinking we should be mathematicians or something...heh. The guy or gal who writes the solution writes it so incoherently that the common man such as myself can't even understand it. So can anyone solve this? (and kindly provide a solution or basis for their answer?) Here it is:
"How many of the three-digit numbers containing no digits other than 2, 3, or 4 are divisible by 3?"
Thanks all! :idea:
 
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dexadental said:
Hey guys...I have a QR question for yall. Kaplan writes this stuff thinking we should be mathematicians or something...heh. The guy or gal who writes the solution writes it so incoherently that the common man such as myself can't even understand it. So can anyone solve this? (and kindly provide a solution or basis for their answer?) Here it is:
"How many of the three-digit numbers containing no digits other than 2, 3, or 4 are divisible by 3?"
Thanks all! :idea:
Click to expand...


Here's my approach. There are six combinations of those 3 digit numbers. The key to this question is a shortcut regarding numbers divisible by 3. If the sum of the digits of a number is divisible by three, then the number itself is divisible by three. The sums of the six possible number combinations below obviously all equal 9, which is divisible by 3 - so I would say the answer to the question is 6.

234
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432
423

I dunno if kaplan expects you to know the shortcut or not, but that's how i would do it. Let me know if i'm wrong.
 
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