This is a QR question from the destroyer.
"In craps you roll 2 dice. You can win on the first roll if you roll a 7 or 11, and you lose if you roll a 2, 3 or 12. What is the probabolity of winning of losing on the first roll?"
Answer: 6 ways to roll a 7, 2 ways to roll an 11 = 8 ways to win
1 way to roll a 2, 2 ways to roll a 3, and one way to roll a 12 = 4 ways to lose
total possible rolls: 6 x 6 = 36
Probaility of winning or losing therefore is 12/36=1/3.
The part I dont understand is where they got the total possbile rolls, they dont state in the question that the person will roll 6 times...what am I missing!?
"In craps you roll 2 dice. You can win on the first roll if you roll a 7 or 11, and you lose if you roll a 2, 3 or 12. What is the probabolity of winning of losing on the first roll?"
Answer: 6 ways to roll a 7, 2 ways to roll an 11 = 8 ways to win
1 way to roll a 2, 2 ways to roll a 3, and one way to roll a 12 = 4 ways to lose
total possible rolls: 6 x 6 = 36
Probaility of winning or losing therefore is 12/36=1/3.
The part I dont understand is where they got the total possbile rolls, they dont state in the question that the person will roll 6 times...what am I missing!?