I just finished going through the sample OAT posted on the ada website and for some reason cant seem to figure out the following QR question:
At 7:00 a.m. a student leaves his home in his automobile to drive to school 28 miles away. He averages 50 mph until 7:30 a.m. when his car breaks down. The student has to walk and run the rest of the way. If he wants to arrive at school at 8:00 a.m. how fast, in mph, must he travel on foot.
Answer: 3
I figure speed = distance/time so for the first half hour the student covers 25 miles (50mph/0.5h) so they have 3 miles left to go in the last half hour 3miles*0.5h = 1. 5 mph?
Where am I going wrong?? 😕
At 7:00 a.m. a student leaves his home in his automobile to drive to school 28 miles away. He averages 50 mph until 7:30 a.m. when his car breaks down. The student has to walk and run the rest of the way. If he wants to arrive at school at 8:00 a.m. how fast, in mph, must he travel on foot.
Answer: 3
I figure speed = distance/time so for the first half hour the student covers 25 miles (50mph/0.5h) so they have 3 miles left to go in the last half hour 3miles*0.5h = 1. 5 mph?
Where am I going wrong?? 😕