QR question
Started by joooj86
Kremlar said:
What about this ADA question:
A Painting whis 4 feet wide and 5 feet long is surrounded by a rectangular frame 6 inches wide. What percent of the area of the picure and the frame is occupied by the frame?
A. 10.5
B. 20
C. 30
D. 33 1/3
E. 50
I have another one:
What is the maximum number of 3 inch squares (square that are 3 inches on a side) that can be cut from a sheet of tin 19X23 inches?
A. 42
B. 48
C. 49
D. 145
E. 146
A Painting whis 4 feet wide and 5 feet long is surrounded by a rectangular frame 6 inches wide. What percent of the area of the picure and the frame is occupied by the frame?
A. 10.5
B. 20
C. 30
D. 33 1/3
E. 50
I have another one:
What is the maximum number of 3 inch squares (square that are 3 inches on a side) that can be cut from a sheet of tin 19X23 inches?
A. 42
B. 48
C. 49
D. 145
E. 146
#1.
A. Square ft of painting = 5 X 4 = 20 sqft
B. Square ft of frame = 6 X 5 = 30 sqft minus 20 sqft (painting) = 10 sqft
C. % of total picture occupied by frame = 10sqft/30sqft = 33.33%
#2.
A. Total possible area to cut from = 19 X 23 = 437 inches
B. Total # of 3 inch squares that can be cut = 437/3 = 145.6
C. Since the question only wants to know the MAX number of WHOLE squares, the answer is 145 and not 146.
A. Square ft of painting = 5 X 4 = 20 sqft
B. Square ft of frame = 6 X 5 = 30 sqft minus 20 sqft (painting) = 10 sqft
C. % of total picture occupied by frame = 10sqft/30sqft = 33.33%
#2.
A. Total possible area to cut from = 19 X 23 = 437 inches
B. Total # of 3 inch squares that can be cut = 437/3 = 145.6
C. Since the question only wants to know the MAX number of WHOLE squares, the answer is 145 and not 146.
Java, for Q#2, im a little confused by your answer....
you used 437/3, why 3 and not 9 (3x3).
Here's my reasoning
take for example a 9"x9" square and divide it into 9 equal parts. You get 9 squares that are 3"x3". Therefore, using these numbers to do Q#2, you have
Total area = 9X9=81"square
Max # of squares = 81/(3x3)= 9 squares
Is my reasoning off here?
you used 437/3, why 3 and not 9 (3x3).
Here's my reasoning
take for example a 9"x9" square and divide it into 9 equal parts. You get 9 squares that are 3"x3". Therefore, using these numbers to do Q#2, you have
Total area = 9X9=81"square
Max # of squares = 81/(3x3)= 9 squares
Is my reasoning off here?
These seem really easy once you break them down, but I can't even get to that part... 😛
9"
________
|__|__|__| 3"
|__|__|__| 3" 9"
|__|__|__| 3"
3" 3" 3"
9"X9" total sides
3"x3" for each square
9 total squares
if you did it Java's way it would come out to
9"X9"=81"
81"/3=27 squares......clearly, from the diagram above, there aren't 27 squares....
but
81"/(3X3)=9=# of squares drawn above.......
________
|__|__|__| 3"
|__|__|__| 3" 9"
|__|__|__| 3"
3" 3" 3"
9"X9" total sides
3"x3" for each square
9 total squares
if you did it Java's way it would come out to
9"X9"=81"
81"/3=27 squares......clearly, from the diagram above, there aren't 27 squares....
but
81"/(3X3)=9=# of squares drawn above.......
makwendo said:
Hmm...I get 42. If you do it Java's way it doesn't make sense to me. So lets figure this out.
Total area: 19 x 23 = 437
If you divide 437/3= 145.6, you are NOT getting the number of 3x3 inch squares. This calculation neglects the size requirement of each square which is 3x3.
Now you may think that 437/(3x3) = 48.5 or 48 squares is the right answer
...but this is another trap. Here you neglecting the requirement that each square be specifically 3x3. Instead you are finding how many "9 area units" will fit into your 19 x 23 sheet. This above calculation will give u odd shaped rectangles of 9x1 or even 4.5x2.
Now heres the answer:
(19/3)= 6.33...so there will be 6 segments of length 3 on this side.
(23/3)=7.66... so there will be 7 segments of length 3 on this side.
Your answer will be 7x6=42. Please dont flame me if im wrong.
Similar threads
