QR Question

[UCF FINatic]

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What is the maximum number of 3-inch
squares (squares that are three inches on
a side) that can be cut from a sheet of tin
19 x 23 inches?
A. 42
B. 48
C. 49
D. 145​

E. 146

So you would find the area of tin:
19*23= 437
Then you find the area of the squares:
3*3= 9
Then you divide it find the number of squares:
437/9 = 48.555555

So how is the answer (A.) 42? Did I do something wrong anywhere?

Thanks for everyones help guys!

 

[Potatochips]

you don't calculate this problem by area. Imagine cutting big square into small little pieces of square in your head. for 19inch side you would be able to fit in 6 3x3 square and for 23 inch side you would be able to fit in 7 3x3 square. Imagine a tile with 6 rows and 7 columns that would make 42 pieces. The rest leftover pieces don't count because you cannot make a 3 inch by 3 square with those.

 

[jas1317]

a cube of 3 inches goes into 19 six times.
a cube of 3 inches goes into 23 seven times.

therefore (6)(7)= 42.

Hope this helped. if not draw it out and you will see.(graphing paper works quite well for this application)👍

 

[UCF FINatic]

you don't calculate this problem by area. Imagine cutting big square into small little pieces of square in your head. for 19inch side you would be able to fit in 6 3x3 square and for 23 inch side you would be able to fit in 7 3x3 square. Imagine a tile with 6 rows and 7 columns that would make 42 pieces. The rest leftover pieces don't count because you cannot make a 3 inch by 3 square with those.

That makes a lot of sense! Thank you so much! 👍