QR trig question

[dentalstudent2021]

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csc^2(x) sin(2x) =?

how do I go about solving these questions ?
I have a hard time even getting started with these. Thanks

 

[Incis0r]

csc^2(x) = 1/(sin x) * 1/(sin x)
sin(2x)=2*(sin x) * (cos x)

so multiply the two terms together. One sin x from numerator cancels with one from denominator.

You get 2 * cos x/(sin x) = 2 * cot (x).