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- Thread starter Sugafoot79
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2. B+C=30,000

3. A=(1/2)C

Therefore, you can plug in the (1/2)C into A in the equation 1 to get:

4. (1/2)C+B=20,000

5. B+C=30,000

Now you have 2 unknowns and 2 equations so you can solve for B and C which can be used to solve for A

Finally, add them up

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Here is another...(I hate trig)

What is the maximum value for the expression 2sin(pi+x) + sin(x) +2?

What is the maximum value for the expression 2sin(pi+x) + sin(x) +2?

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Here is another...(I hate trig)

What is the maximum value for the expression 2sin(pi+x) + sin(x) +2?

The largest value any sin or cos can have (as long as there's no irregularities inside the () argument) is 1.

So the max of this expression is 2*1+1+2 = 5

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Note that sin(pi+x) = sin(pi)cos(x) + cos(pi)sin(x) = -sin(x).Here is another...(I hate trig)

What is the maximum value for the expression 2sin(pi+x) + sin(x) +2?

So you have -2sin(x) + sin(x) + 2..

So you really have 2 - sin(x). The way to maximize this is to make sin(x) as LOW as possible. This would be -1. So the maximum value is 3.

Use x = 3pi/2 and get a max value of 3.

Edit: Shinpe there's a pi in one of those parentheses.

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Note that sin(pi+x) = sin(pi)cos(x) + cos(pi)sin(x) = -sin(x).

So you have -2sin(x) + sin(x) + 2..

So you really have 2 - sin(x). The way to maximize this is to make sin(x) as LOW as possible. This would be -1. So the maximum value is 3.

Use x = 3pi/2 and get a max value of 3.

Edit: Shinpe there's a pi in one of those parentheses.

I guess I should have taken my own advice on looking inside the parenthesis more seriously lol

Thanks for correction

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. nvm

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Note that sin(pi+x) = sin(pi)cos(x) + cos(pi)sin(x) = -sin(x).

So you have -2sin(x) + sin(x) + 2..

So you really have 2 - sin(x). The way to maximize this is to make sin(x) as LOW as possible. This would be -1. So the maximum value is 3.

Use x = 3pi/2 and get a max value of 3.

Edit: Shinpe there's a pi in one of those parentheses.

Couple of questions:

sin(pi+x) = sin(pi)cos(x) + cos(pi)sin(x) = -sin(x)

is this a function I should memorize. Curious..how was this deduced?

Also, how did you know to use -1?

Did you use the graph of y=sinx/y=cosx?

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Couple of questions:

sin(pi+x) = sin(pi)cos(x) + cos(pi)sin(x) = -sin(x)

is this a function I should memorize. Curious..how was this deduced?

Also, how did you know to use -1?

Did you use the graph of y=sinx/y=cosx?

sin(x+y) = sin(x)cos + sincos(x)

(sine of the first * cosine of the second) plus (sine of the second * cosine of the first)

Sub in a minus sign in the middle if it's sin(x-y).

For cos:

cos(x+y) = cos(x)cos - sin(x)sin

Sub in a plus sign in the middle if it's cos(x-y).

===

I chose -1 since I wanted the largest value for 2 - sin(x).

If you had 2-y and I said y lies between -1 and 1, what would you choose for y to make 2-y the largest? You would choose -1. So that's why I wanted sin(x) to be -1.

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OMG! I luv you!!! Thanks a bunch!!!

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Evaluate:

(t^2+2t+4)/(t+1)

Thanks again!!!

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It doesn't divide evenly since the numerator doesn't factor into (t+1) * something. You need to do long division...New Question:

Evaluate:

(t^2+2t+4)/(t+1)

Thanks again!!!

t+1 into t^2 + 2t + 4

Always put them in decreasing exponential order (highest power first, constant term last) and make sure you fill in the gaps if there's an exponent missing!! If you had t^2 + 1 you'd need to write it as t^2 + 0t + 1.

t goes into t^2, t times. So write a 't' at the top.

Multiply through by t: t * (t+1) = t^2 + t. Subtract from t^2 + 2t + 4.

Get t + 4.

Repeat. t goes into t, 1 time. So you have a +1 up top now. So you have t + 1.

Multiply through by 1: 1 * (t+1) = t+1. Subtract.

That's your remainder.

Okay I had to go to dinner at that point. Here's the rest:

Subtract the t+1 and get 3 left over. Since t can't go into 3, you're done. You have 3 as a remainder. Proper notation is:

Answer (t+1) remainder 3/(t+1)

or

t + 1 + [3/(t+1)]

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Man Street, ur the best. It's been awhile since I've done long division with polynomials. Thanks again.

P.S. Be on the look out. I'll be posting more QR's questions. Thanks again.

P.S. Be on the look out. I'll be posting more QR's questions. Thanks again.

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A mother is twice as old as her son. 12 years ago, the ratio of the mother and son age was 5:2. What was the mother's age 2 years ago?

I hate working with word problems and ratios.

S = son

M=2S

12 years ago...

(M-12)/(S-12) = 5/2

Then you get 2M-24 = 5S-60

Substitute M=2S

Then; 4S-24 = 5S-60

-S = -36 or S=36

M = 2(36) = 72

2 Years ago she was 70

To double check (M-12) = 60 and (S-12) = 24, and 60/24 = 5/2

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Nicely done!

Here is another of which I can't figure out:

If z=x-3, then the value of z+1/z is?

Here is another of which I can't figure out:

If z=x-3, then the value of z+1/z is?

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Man Street, ur the best. It's been awhile since I've done long division with polynomials. Thanks again.

P.S. Be on the look out. I'll be posting more QR's questions. Thanks again.

I haven't seen a math question go unanswered by him in two years....he is good.

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I haven't seen a math question go unanswered by him in two years....he is good.

I know street is awesome!

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Here is how CDM explains it:

z+(1/z) = (x-3) + 1/(x-) = ((x-3)^2 +1)/(x-3) = (10-6x+x^2)/(x-3)

I don't understand how they got (x-3)^2 (see red highlight above)...

z+(1/z) = (x-3) + 1/(x-) = ((x-3)^2 +1)/(x-3) = (10-6x+x^2)/(x-3)

I don't understand how they got (x-3)^2 (see red highlight above)...

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Look harder... I've missed a fewI haven't seen a math question go unanswered by him in two years....he is good.

Some other good math people around.

z + 1/z = (x-3) + 1/(x-3)

multiply the first term by (x-3)/(x-3) to set the same denominator so you can add them together:

(x-3)(x-3)/(x-3) + 1/(x-3)

etc until you get the answer.

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OMG!!! I'm a ****ing idiot!!! Thanks!

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answer is m-1

Im confused

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http://forums.studentdoctor.net/showthread.php?t=645168&highlight=If+N+is+any+positive+integer

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http://forums.studentdoctor.net/showthread.php?t=645168&highlight=If+N+is+any+positive+integer

thanks man

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http://forums.studentdoctor.net/showthread.php?t=645168&highlight=If+N+is+any+positive+integer

Lol, literally man....

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