question about rate law.

[savvysearch]

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Last question. I promise! I take my test tommorrow.

In basic solution:

(Ch3)3CCl + OH- -----> (CH3)3COH + Cl-

Mechanism:
(CH3)3CCl ---->(CH3)C+ + Cl- (fast)
(Ch3)C+ + OH- ----->(CH3)3COH (slow)

what is the rate?

I thought the rate was the product of conc. of reactants of the slow part. So, k[(CH3)C][OH]=rate

But, the answer is: [(CH3)3CCl][Cl-]

Why?

 

[savvysearch]

oh, and 1 more.

Zn2+ has an electron configuration of [Ar]4s^0 3d^10

I thought it was [Ar]4s^2 3d^8. why?

 

[croco]

Due to the fact that C(CH3)3+ does not form unless the fast reaction occurs. So if the rate shows over a perios of "time" that CCH3CL concentration decreases and CL- concentration increases you can assume that C(CH3)3+ has been formed. Just ask yourself, how can the slow step occur without the cation?

#2 -- I believe if I recall correctly, there were 2 or 3 transition elements that behave the same way that zinc does. Just look in your textbook.

 

[savvysearch]

thanks a lot!

 

[ShawnOne]

good luck saavysearch! Let us know how you do.