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DAT Destroyer

Dr. Romano and Nancy
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I received this PM and thought I would share with the board to help others who are studying.

Hi Dr. Romano

I was wondering if you could help clarify this for me: I know that when you have something like Mg(OH)2 with a conc of 0.1, then the OH is 0.1*2=0.2 Would you do the same for something with more than one proton, like H2SO4, say 0.6 M..would the H+=1.2 then? I know that for those n1m1v1 problems, you would put 2 for n1 if using h2so4, but I might have just forgot about this for acids with the concentration.

Thanks in advance!


Answer:

Yes.....For H2SO4.......consider a 0.6M solution as 1.2 M in Hydronium ions.
 
I received this PM and thought I would share with the board to help others who are studying.

Hi Dr. Romano

I was wondering if you could help clarify this for me: I know that when you have something like Mg(OH)2 with a conc of 0.1, then the OH is 0.1*2=0.2 Would you do the same for something with more than one proton, like H2SO4, say 0.6 M..would the H+=1.2 then? I know that for those n1m1v1 problems, you would put 2 for n1 if using h2so4, but I might have just forgot about this for acids with the concentration.

Thanks in advance!


Answer:

Yes.....For H2SO4.......consider a 0.6M solution as 1.2 M in Hydronium ions.

I'm glad I gave him the same answer too, that would have been embarrassing haha
 
Can't you just use NaMaVa=NbMbVb?

If the acid and the base both gave off one hydronium ion they would just cancel?


Sent from my iPhone using Tapatalk
 
Can't you just use NaMaVa=NbMbVb?

If the acid and the base both gave off one hydronium ion they would just cancel?


Sent from my iPhone using Tapatalk

Yes.....If the acid has 1H, and the base 1 OH....either MaVa = MbVb or NaVa = NbVb.

However,,,,,be careful with this !

I prefer to always use NaVa = NbVb formula.

Dr. Jim Romano
 
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