Which of the following pairs of molecules does not have the central atom (transition metal) with the same number of d-electrons in both compounds?
A) Fe(NH3)63+ and FeCl63-
B) Co(H2O)63+ and MnCl64-
C) Cr(NH3)63+ and MoCl63-
D) Os(NH3)42+ and RhCl3(Pr3)3
Answer & their reasoning:
B) Co(H2O)63+ and MnCl64-
To determine the # of electrons on the central metal, the formal charge of the metal first must be determined. From the charge, the electronic configuration is found, so the d-electron count is found.
Choice A is eliminated:
Fe carries a +3 charge in both Fe(NH3)63+ and FeCl63-. Is this actually true? I'm really confused by this one.
Choice B is correct:
Co carries a +3 charge in Co(H2O)63+, and Mn carries a +2 charge in MnCl64-. Neutral Co is [Ar]4s23d7, so Co3+ has a d-electron count of 6 (3d6). Neutral Mn is [Ar]4s23d5, so Mn2+ has a d-electron count of 5 (3d5).
Choice C is eliminated:
Cr carries a +3 charge in Cr(NH3)63+, and Mo carries a +3 charge in MoCl63-. Neutral Cr is [Ar]4s13d5, so Cr3+ has a d-electron count of 3 (3d3). Neutral Mo is [Kr]5s14d5, so Mo3+ has a d-electron count of 3 (4d3). The d-electron counts are equal.
Choice D is eliminated:
Os carries a +2 charge in Os(NH3)42, and Rh carries a +3 charge in RhCl3(Pr3)3. Neutral Os is [Xe]6s24f145d6, so Os2+ has a d-electron count of 6 (5d6). Neutral Rh is [Kr]5s24d7, so Rh3+ has a d-electron count of 6 (4d6).
A) Fe(NH3)63+ and FeCl63-
B) Co(H2O)63+ and MnCl64-
C) Cr(NH3)63+ and MoCl63-
D) Os(NH3)42+ and RhCl3(Pr3)3
Answer & their reasoning:
B) Co(H2O)63+ and MnCl64-
To determine the # of electrons on the central metal, the formal charge of the metal first must be determined. From the charge, the electronic configuration is found, so the d-electron count is found.
Choice A is eliminated:
Fe carries a +3 charge in both Fe(NH3)63+ and FeCl63-. Is this actually true? I'm really confused by this one.
Choice B is correct:
Co carries a +3 charge in Co(H2O)63+, and Mn carries a +2 charge in MnCl64-. Neutral Co is [Ar]4s23d7, so Co3+ has a d-electron count of 6 (3d6). Neutral Mn is [Ar]4s23d5, so Mn2+ has a d-electron count of 5 (3d5).
Choice C is eliminated:
Cr carries a +3 charge in Cr(NH3)63+, and Mo carries a +3 charge in MoCl63-. Neutral Cr is [Ar]4s13d5, so Cr3+ has a d-electron count of 3 (3d3). Neutral Mo is [Kr]5s14d5, so Mo3+ has a d-electron count of 3 (4d3). The d-electron counts are equal.
Choice D is eliminated:
Os carries a +2 charge in Os(NH3)42, and Rh carries a +3 charge in RhCl3(Pr3)3. Neutral Os is [Xe]6s24f145d6, so Os2+ has a d-electron count of 6 (5d6). Neutral Rh is [Kr]5s24d7, so Rh3+ has a d-electron count of 6 (4d6).