I need help with this question. How come this compound is not a meso compound. You have exactly the same substituents on both sides so why its not a meso compound?
How many chiral centers do this compound have?So for a compound to be meso, you need atleast 2 chiral centers (C bound to 4 different groups) and have a line of symmetry (Can be folded on this self)
They both have 2How many chiral centers do this compound have?
If a meso compound has to have at least 2 chiral centers... you indicated to me that there are 2 chiral centers for both compounds. So I want to know more how they are not meso compounds.
Nicely said!This is only half of what he/she said. They said that to be a meso compound it has to have two chiral centers AND have a line of symmetry. A line of symmetry is when you draw an imaginary line down the center and one side looks EXACTLY like the other (keep in mind certain bonds can rotate and may not appear symmetrical at first, although this is not the case here because it's a ring). Compound two meets both criteria. Compound one doesn't.