Question on Power = Fv cos()

[sicboy188]

i understand the derivation to this equation

Power = ∆W/∆t = Fdcos(&#952😉/∆t = Fv cos(&#952😉


but what exactly does the velocity refer to. wouldnt it have to be the average velocity over the ∆t because if a force is doing work on the object, than its v must be changing... right?


please to elucidate....

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[justpremed]

correct...F = ma in all cases, and if you have a force, assuming that mass isn't 0, then acceleration can't be 0, so velocity must be changing, and you have to use the average velocity over a time period

 

[sicboy188]

sweet. thanks for the quick response.

this and impulse were always mathematical derivations that made sense to me in the math realm, but not in the physical world.

thanks again.