Quick math question [Circular Permeutation]

[DrTacoElf]

6 people around a table - number of possible combinations. How to approach this escapes me but adding one to 6 comes to mind for some reason. Also how would this circular permeutation differ from a linear one like 6 people in a line number of possible combinations.


Thanks if you can help.

 

[DrTacoElf]

Doh found the answer myself 🙂

http://mathworld.wolfram.com/CircularPermutation.html

 

[balance]

it is 5!, since order does not matter around the circular table, so you would need to consider two of the people as one (6-1)!

Good luck