Quick Ochem Q
Started by johblip
Yes! Sometimes it's all they ask for.
E. Name reactions
1. Grignard
2. Wittig
3. Diels-Alder
4. Aldol reaction
Looking at the DAT OC section, those are the four I need to be able to name?
Also, Chad presented his HNMR stuff with labels (2H, 1H, 3H, etc...) while destroyer omits these labels. Which is it on the DAT?
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Yes. Sometimes questions refer to the names of the reactions.
Those names should keep you covered. Check out aqz's breakdown, I think he may mention a few more.
I didn't have any HNMR questions on my exam, but you need to understand what those mean - they refer to the area under the curve. If a curve has "2H" above it, it means there are two hydrogens that are being split.
Yep, and there are also names in other parts that belong under SN1/SN2/E1/E2 and reactions of alcohols etc. Some that come to mind include Friedal Crafts, Fischer esterfication, and so on.
I don't think you'll get something with labels on the DAT (2H, 1H), but you should still know what it means. It'll help understand everything else including the basics more.
I would stop looking at the exam as a bunch of questions of "What do I need to not know?" and more towards "I don't know this, let me cover it again". These questions all are just little pieces of the pie and direct recall. When you start cutting a lot of corners it's going to reflect on your DAT scores. Learn it for the sake of learning it.
It's better to know it and not need it, than need it and not know it.
I agree, I just wanted to make sure I was spending my time learning something that would be tested within the scope of the DAT (as opposed to studying obscure reaction names that would never be a possible question in the first place.)
I have another question, iirc Chad mentioned that for each C signal, there should be its corresponding signal on the NMR spectra. However, in Destroyer question 216 (2012 edition) the answer B possesses 5 signals but only 4 are showing on the spectra. Why is that?
The NMR shows signals at ~2.3, 5, ~6.7, 6.9. The answer was: 4-methylphenol.
I have the newer Destroyer, but I believe your question is the same as number 228 in the 2013 Ed. This questions is referring to proton NMR, not C NMR. There are 4 different hydrogens environments in the molecule. Keep in mind that there are no hydrogens attached to any benzene carbons that have substituents.
