so the question goes;
if csc a = - Square root of 2 find COS a in the third quadrant.
Ok great, so i figured out the value which was square root of 2 over 2, but in the third quadrant cos is negative, yet the actually value is ALREADY negative so dont you negate both negatives to give you a positive answer?
The math destroyer gives - square root of 2 / 2 as the answer, but i think it is just square root of 2/ 2 ....
Hope this makes senses..
Btw its question # 3 on practice test 9
if csc a = - Square root of 2 find COS a in the third quadrant.
Ok great, so i figured out the value which was square root of 2 over 2, but in the third quadrant cos is negative, yet the actually value is ALREADY negative so dont you negate both negatives to give you a positive answer?
The math destroyer gives - square root of 2 / 2 as the answer, but i think it is just square root of 2/ 2 ....
Hope this makes senses..
Btw its question # 3 on practice test 9