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QVault GC Help Please!
Started by hope_to_match
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yeah and i keep reading on wiki and i dont understand the concept 🙁
Well you can derive the concept...If oxygen gas has solubility of 1.25x10^-4 in water at 1 atm, where the partial pressure of oxygen is .21atm (.21mol*1atm). meaning 21 out of 100 "gas particles" have a chance to go into the liquid, while the solubility will reduce that number since not all O2 is dissolved. Think the solubility as how much O2 will not dissolve, to balance that concentration of O2 in liquid vs atmosphere. So if you increase the number of gas particles (in this case 100/100) then the solubility of O2 should increase...
now the math....
(Pressure of gas)/(KH) = Concentration where KH is the solubility of gas in water.
So you have two equations set it to each other, since the concentration will stay the same (I like it to view it as "equilibrium")
(.21atm)/(1.25*10^-4)=(1atm/x)
.21x = 1.25*10^-4
x = (1.25*10^-4)/.21
This might help...
http://www.khanacademy.org/science/healthcare-and-medicine/the-lungs/gas_exchange/v/henry-s-law
now the math....
(Pressure of gas)/(KH) = Concentration where KH is the solubility of gas in water.
So you have two equations set it to each other, since the concentration will stay the same (I like it to view it as "equilibrium")
(.21atm)/(1.25*10^-4)=(1atm/x)
.21x = 1.25*10^-4
x = (1.25*10^-4)/.21
This might help...
http://www.khanacademy.org/science/healthcare-and-medicine/the-lungs/gas_exchange/v/henry-s-law
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