-
CycleTrack and SDN are teaming up to make medical school admissions more transparent and accessible! Read the announcement to learn how we’re supporting the future of CycleTrack’s free application-tracking tools .
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an alternative browser.
You should upgrade or use an alternative browser.
Qvault OC Question
Started by hope_to_match
Get help with your application
Use all the free resources available to you from SDN: articles, guides, expert advising, forums discussions, and school research.
The best reagent is the one that inhibits E1/SN1...so we want a strong base.
so in cases like this E2 is preferred over E1?
Just out of curiosity, if this reaction was to proceed via E1, would the carbocation shift to the left to be allylic to the benzene ring?
Either way, I see Eugeniager's point...either E1 or E2 would give the same major product here. Is there a specific reason we would want to go E2?
Either way, I see Eugeniager's point...either E1 or E2 would give the same major product here. Is there a specific reason we would want to go E2?
Last edited:
Just out of curiosity, if this reaction was to proceed via E1, would the carbocation shift to the left to be allylic to the benzene ring?
Either way, I see Eugeniager's point...either E1 or E2 would give the same major product here. Is there a specific reason we would want to go E2?
yeah that's what I am confused about..hope flavor will comment further on this. i guess what he means is that E2 or preferred over E1? 😕
E1 also gets you SN1 products. E2 will not also get you sn2 products because it's a tertiary carbon/hindered.
E1 also gets you SN1 products. E2 will not also get you sn2 products because it's a tertiary carbon/hindered.
👍
Notice, the question says "best".
