bobeanie95 Full Member 7+ Year Member Joined Apr 19, 2016 Messages 226 Reaction score 139 Jul 19, 2016 #2 I ran into the same problem, does anyone understand the reasoning behind this? Upvote 0 Downvote
theonlytycrane Full Member 10+ Year Member Joined Mar 23, 2014 Messages 2,127 Reaction score 2,276 Jul 19, 2016 #3 As we add I- (to be oxidized), we start out with the full cell potential of .36V. At the end of the titration, the potential will be 0V. The equivalence point (halfway) will be the point where the full cell potential is cut in half. Upvote 0 Downvote
As we add I- (to be oxidized), we start out with the full cell potential of .36V. At the end of the titration, the potential will be 0V. The equivalence point (halfway) will be the point where the full cell potential is cut in half.
bobeanie95 Full Member 7+ Year Member Joined Apr 19, 2016 Messages 226 Reaction score 139 Jul 19, 2016 #4 @theonlytycrane thank you! Upvote 0 Downvote