Resistors and capacitors in series

[Tokspor]

If there's an emf connected to two resistors in parallel followed by a capacitor, would this be an open circuit, and therefore no voltage or current would be running? I drew something quickly below to show what I mean.

I know that for a capacitor in parallel with a resistor, if there was an emf, the capacitor would be charged with the same amount of voltage as the resistor, but what about for a situation like the one below?

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[Spiker]

Having capacitor does not mean it is open circuit. The energy is used to build up charges on different side of the compacitor. there are current going into and out of the compactor just not across, while it is charging.

 

[Pulsar]

If there's an emf connected to two resistors in parallel followed by a capacitor, would this be an open circuit, and therefore no voltage or current would be running? I drew something quickly below to show what I mean.

I'm not really sure I know what you mean by this. Where are you applying the EMF?

 

[Tokspor]

The emf is represented on the lower left side of the figure (the one with short dash and a long dash). Let's say it has 10 V. Now I now that for the parallel resistors, an equal voltage should run through both. However, because there is a capacitor in series with them, does this mean the voltage is still 10 V for the resistors, or is it 5 V for each resistor and 5 V for the capacitor?

Also, shouldn't current only run through resistors and not capacitors?

 

[Spiker]

They dont run though capacitor while it is runing. However the current is putting electron on one side and taking away electron from other side. so while there is no current going through it, there is still current in the circuit while it is building up. and yes when it is charged there is no current until it discharge.

 

[Tokspor]

They dont run though capacitor while it is runing. However the current is putting electron on one side and taking away electron from other side. so while there is no current going through it, there is still current in the circuit while it is building up. and yes when it is charged there is no current until it discharge.

Okay, thanks. So when the capacitor is being charged, is the voltage running across the resistors 10 V or 5 V if the emf has 10 V?

And once charged, the capacitor would discharge electrons from the bottom plate to the side of the emf represented by the short dash, while the top plate would "discharge" positive charge through the resistors and onto the other side of the emf, correct?

 

[Spiker]

didnt do the calculation but sounds right.

 

[Pulsar]

Okay, thanks. So when the capacitor is being charged, is the voltage running across the resistors 10 V or 5 V if the emf has 10 V?

You can't quantify the voltage on each component without knowing the capacitance of the capacitor. But it's not 10. And it's not just half (5v). You have to take the capacitance into account.

The voltage on the capacitor is given by Q/C. Since Q is initially zero before you charge it, the voltage on the resistors must start at 10v. But this is only at t=0. At that infinitesimally small instant. This is the only time the voltage on the resistor will ever be 10. As the voltage on the cap grows, the voltage across the resistors must drop so the sum is always equal to 10v. After the cap is fully charged, the resistor's voltage is zero and the cap. voltage is 10.