rotational KE of electrons in diff orbits?

[thestormpetrel]

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if we solve the formula of rotational kinetic energy we get linear kinetic energy, this means that the value of a rotating body is equal to the value of 1/2mv^2 where v is its linear velocity, right or not?
IF the above statement is right then since the velocity of electrons in higher orbits is less and mass is same, so the rotational kinetic energy of an electron would also be less in higher orbits, right or not? (the r would be bigger but if we solve the formula, the r^2s cancel out, right?)

 

[sps27]

if we solve the formula of rotational kinetic energy we get linear kinetic energy, this means that the value of a rotating body is equal to the value of 1/2mv^2 where v is its linear velocity, right or not?
IF the above statement is right then since the velocity of electrons in higher orbits is less and mass is same, so the rotational kinetic energy of an electron would also be less in higher orbits, right or not? (the r would be bigger but if we solve the formula, the r^2s cancel out, right?)

Rotational KE = 1/2 * (angular velocity)2 * moment of Inertia.....So I am wondering how you equated that to translational KE = I/2 * (v)2 * mass. Moment of Inertia is not exactly mass.

 

[thestormpetrel]

Rotational KE = 1/2 * (angular velocity)2 * moment of Inertia.....So I am wondering how you equated that to translational KE = I/2 * (v)2 * mass. Moment of Inertia is not exactly mass.

1/2*I*w^2 where I is equal to mr^2 and w^2 is equal to v^2/r^2. the r^2s cancel out and we are left with 1/2mv^2. i guess.

 

[milski]

Where exactly are you headed with this? Electrons don't actually rotate in circular orbits and applying classical mechanics to them does not really work. 😕