simple O-chem question.......

[sminj85]

---

Members don't see this ad.

I am confused between activity and acidity.
1.I thought e- withdrawing group increases acidity but decreseas activity. Is it wrong?

2. NH3 vs CH3H2OH .. which one is higher activity?

Thx..

 

[Decan]

What do you mean by activity?

 

[IsRaEl21]

e- withdrawing groups increase acidity and deactivate the aromatic ring( if that what u mean by activating) so COOH, SO3H, NO2, CF3 CN are deactivating the ring therefore they go meta. Halogens also deactivate the ring but they go Orth Para. e- donating groups are activating the ring and they are NH2, O-R , OH CH3 they are all activating the ring. Activating I mean speed up the rx.

I really think NH3 has a higher activity than CH3 group

( I really couldn't understand ur question but this is the best I could do, If u need help PM me)
I really think u should get the destroyer don't even read Kaplan I wasted my time by reading Kaplan. Destroyer has the best explanations that I have ever seen. Achiever is also good for practice.
Good Luck !!!!!!!!!!!!!!!!!!!!!!!!!1

 

[Adamska]

However, none of this means anything unless you have a reference point: activate wrt what?

NH3, CH3, OH, all activate ELECTROPHILIC aromatic substitution rxns and are ortho, para directors, the reason being that the charge on the cyclohexadienyl cation intermediate is better stabilized through resonance at these positions. Meanwhile, NO2 and CF3 and the like deactivate and are meta directors. However, it is important to note that halogens are slightly deactivating and ortho, para directing (because while they are to an extent EWG, their excess of lone pairs lets them stabilize the cation at these positions).

With NUCLEOPHILIC aromatic substition, however, the situation is reversed...the carbanion intermediate favors the opposite method. Keep in mind that because it is nucleophilic, you need a good LG for this type (as opposed to a simple proton doing the trick in EAS), such as a chloride.