- Joined
- Jun 1, 2009
- Messages
- 440
- Reaction score
- 5
The Ka for HSO4- is 1.2E-2. When 1 mole of HSO4- is added to one liter of pure water:
A. the ion completely dissociates
B. most, but not all, of the ions gain a proton
C. most, but not all, of the ions lose a proton
D. some of the ions lose a proton, but most of the ions neither gain nor lose a proton
Answer: D
OK, so I understand this question mathematically. Ka = 1.2E-2 = x^2/1
x = 1.1E-1, which is [H+] which is less than 1 so D is the answer.
But what's not working for me is the Ka being 1.2E-2, which means the pKa is just under 2. Why isn't there more dissociation?? Doesn't the low pKa mean that there should be significant dissociation?
I guess I get stuck on the fact that for buffers the pKa is the pH at which there's equal concentrations of A-/HA. Any help with getting me to process this? lol
A. the ion completely dissociates
B. most, but not all, of the ions gain a proton
C. most, but not all, of the ions lose a proton
D. some of the ions lose a proton, but most of the ions neither gain nor lose a proton
Answer: D
OK, so I understand this question mathematically. Ka = 1.2E-2 = x^2/1
x = 1.1E-1, which is [H+] which is less than 1 so D is the answer.
But what's not working for me is the Ka being 1.2E-2, which means the pKa is just under 2. Why isn't there more dissociation?? Doesn't the low pKa mean that there should be significant dissociation?
I guess I get stuck on the fact that for buffers the pKa is the pH at which there's equal concentrations of A-/HA. Any help with getting me to process this? lol