Can someone explain why this is SN2 and not E2? this is driving me crazy!!!
CH3CH2CH2BR + (CH3)3P in (CH3OH) ------>
please help!!!
Eh the above response is partially correct.
It is primary, so IF YOU DON'T HAVE A BULKY BASE, its SN2. If you are reacting with something like tert-butoxide however, it is E2.
Also, E2 reactions usually have strong bases. (CH3)3P is a strong Nucleophile, not a strong base.
You should memorize those (NaH, NaOH, NaNH2...basically anything with a - sign. Note that the ones I just named ARE negatively charged, but they are ionically complexed with a metal. So ignore the metal when you see it, and recognize the base with a charge. ie. NaOH is really -OH. But that only works if its a metal in front. ie. CH3OH will not split apart/dissociate in solution, thus it is not -OH, but CH3OH, a weaker base than -OH (or NaOH as it is commonly written).
Also, know the most common nucleophiles- anythign with a P (ie. (CH3)3P in the above rxn) or an S are the most common. Nuceophiles react in SN reactions, and bases react in E reactions.
Weak nucleophiles generally are in SN1 reactions.
Strong nucleophiles are usually in SN2 rxns
Weak Bases E1
Strong Bases E2
Don't just memorize the trend. Know which bases/nucleophiles are strong/weak.
Also know which leaving groups are best. For instance, if the above substrate had an I, would it react faster or slower?
You want to make sure you have a great handle on this for the DAT, as it will DEFINITELY show up.