SN2 inversion of products?

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tnmoonprism

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Hello,
I was wondering if anyone has any insight into when we do an SN2 with a reactant with more than 1 chiral centers, will the products be the inversion of ALL those chiral centers or just the one that was attacked?
Thank you!
 
Thanks guys!
So that means if the reactant has more than 1 chiral centers, our product will be the DIASTEREOMER and not the enantiomer of the reactant right?
 
Hello,
I was wondering if anyone has any insight into when we do an SN2 with a reactant with more than 1 chiral centers, will the products be the inversion of ALL those chiral centers or just the one that was attacked?
Thank you!

Let us do an example......Consider CN- reacting with 2-fluoro-4 iodooctane. The CN- reacts with the Iodine in SN2 fashion,.....and inverts this carbon. Fluorine is a poor leaving group thus will not react. Thus.....we inverted the carbon bearing the iodine....and left the carbon bearing the fluorine alone.

I hope this helps.

Dr. Romano
 
Let us do an example......Consider CN- reacting with 2-fluoro-4 iodooctane. The CN- reacts with the Iodine in SN2 fashion,.....and inverts this carbon. Fluorine is a poor leaving group thus will not react. Thus.....we inverted the carbon bearing the iodine....and left the carbon bearing the fluorine alone.

I hope this helps.

Dr. Romano

Ohhhhh It finally makes sense! Thank you Dr. Romano!
 
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