This comes from Chad's quizzes.
What is most soluble in benzene
A.CH3CH2CH2OH
B.CH3CH2OH
C.HOCH2CH2OH
D.CH3CH2CH2CH2CH2OH
I guess I understand that since they are all capable of H-bonding, they are all polar. Since D has the largest "non-polar" area, it will be most soluble.
Here is my question though, I initially looked all of the answers and saw they all had -OH but then I looked at C and saw that it was a symmetrical compound, and I assumed that the molecule would be non-polar overall. Thus being most soluble in benzene. How Chad explains it, I guess C would actually be the least soluble since it has multiple areas of H-bonding.
But is it not safe to say if a molecule is symmetrical it will be non-polar? Should I just go with if ANYTHING has hydrogen bonding, it will be polar?
What is most soluble in benzene
A.CH3CH2CH2OH
B.CH3CH2OH
C.HOCH2CH2OH
D.CH3CH2CH2CH2CH2OH
I guess I understand that since they are all capable of H-bonding, they are all polar. Since D has the largest "non-polar" area, it will be most soluble.
Here is my question though, I initially looked all of the answers and saw they all had -OH but then I looked at C and saw that it was a symmetrical compound, and I assumed that the molecule would be non-polar overall. Thus being most soluble in benzene. How Chad explains it, I guess C would actually be the least soluble since it has multiple areas of H-bonding.
But is it not safe to say if a molecule is symmetrical it will be non-polar? Should I just go with if ANYTHING has hydrogen bonding, it will be polar?