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If I have two chemicals mixed in the liquid phase that have the same boiling point, is the beginning boiling point for for both of them now reduced somewhat or does it stay the same?
Let's say I mix hexane with water, and then I bring the heat up to just below the boiling point of hexane(which should be much lower than that of water), it does boil sooner now, right? even though water has a higher bp. Then the hexane can sort of "carry" the water molecules with it? This book doesn't explain this distillation stuff at all.
I'm also having trouble with figuring out how I'm supposed to convert optical rotation into specific rotation. Assuming I used a "length" of 3cm and and solution that was 2g/ml. Is it just (observed rotation)/ ((10/3) cm(1/2) grams per ml). I guess this one wasn't very conceptual. Oh well.
Let's say I mix hexane with water, and then I bring the heat up to just below the boiling point of hexane(which should be much lower than that of water), it does boil sooner now, right? even though water has a higher bp. Then the hexane can sort of "carry" the water molecules with it? This book doesn't explain this distillation stuff at all.
I'm also having trouble with figuring out how I'm supposed to convert optical rotation into specific rotation. Assuming I used a "length" of 3cm and and solution that was 2g/ml. Is it just (observed rotation)/ ((10/3) cm(1/2) grams per ml). I guess this one wasn't very conceptual. Oh well.