Could someone please how B is the correct answer here http://i.imgur.com/FAtmL.png.
From what I understand of the question. It seems to me that E should be the correct answer since having one copy of Beta-A-Globin (wild type allele) should give you 2 fragments (0.2 and 1.15kb) and having one copy of Beta-S-Globin (sickle cell allele) should give you 1 fragment (1.35kb). So shouldn't a carrier have all three fragments?
EDIT: Nevermind. I didn't think about where the probe would bind. The 0.2kb fragment will never show up on the southern blot since the probe doesn't bind to it... Now I feel dumb.
From what I understand of the question. It seems to me that E should be the correct answer since having one copy of Beta-A-Globin (wild type allele) should give you 2 fragments (0.2 and 1.15kb) and having one copy of Beta-S-Globin (sickle cell allele) should give you 1 fragment (1.35kb). So shouldn't a carrier have all three fragments?
EDIT: Nevermind. I didn't think about where the probe would bind. The 0.2kb fragment will never show up on the southern blot since the probe doesn't bind to it... Now I feel dumb.