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I seem to be confused with Spontaneity and overall thermodynamics at this point. I think it's due to the fact that we use enthalpy synonymously as heat. I understand that if ΔG is negative, the reaction is always spontaneous. Also meaning it is exothermic favoring the products. But if a reaction gives a negative ΔH, it is exothermic, releasing heat and also spontaneous. Is this ΔH also like the enthalpy like we see in the following equation and Spontaneity cases? If so, how is that we can ever have a reaction with negative enthalpy and be non-spontaneous at high temperatures like what we see below in the 4th case? Thanks!
using ΔG= ΔH - T ΔS, we see the cases:
- ΔH & + ΔS = Spon @ all T
+ ΔH & - ΔS = Non-Spon @ all T
+ ΔH & + ΔS= Spon @ High T
- ΔH & -ΔS = Spon @ Low T
using ΔG= ΔH - T ΔS, we see the cases:
- ΔH & + ΔS = Spon @ all T
+ ΔH & - ΔS = Non-Spon @ all T
+ ΔH & + ΔS= Spon @ High T
- ΔH & -ΔS = Spon @ Low T