Stable Conformation

[wizi]

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Hi guys,

I have a question on Destroyer Organic #9.

Q: The most stable conformation of (trans)-1-bromo -3- methylcyclohexane is?

A: Methyl is equatorial, Br is axial.


My question is: what if they change (trans)-1-bromo -3- methylcyclohexane to (trans)-1-bromo -4- methylcyclohexane????

Is the answer going to be same?

Thank you,

 

[rav4182]

Hi guys,

I have a question on Destroyer Organic #9.

Q: The most stable conformation of (trans)-1-bromo -3- methylcyclohexane is?

A: Methyl is equatorial, Br is axial.


My question is: what if they change (trans)-1-bromo -3- methylcyclohexane to (trans)-1-bromo -4- methylcyclohexane????

Is the answer going to be same?

Thank you,

then they'd both be equitorial. draw it out

 

[yappy]

1-4 would be a trans cyclo with both the br and methyl group in the equitoral position.

Notice how the methyl group is below the H and the bromo is above the H = trans

***note: I did not put in H's coming off the chain. Just imagine them there.

Check her out:

 

[invictusx]

Both are equatorial. Equatorial positions are best because axial positions cause steric hindrance. That's why glucose is such an amazing molecule. All its substituents are in equatorial position in chair form. 👍

 

[wizi]

Thank you so much guys. I got it.