H henrygl Junior Member 10+ Year Member 15+ Year Member Joined May 22, 2006 Messages 8 Reaction score 0 Points 0 May 25, 2006 #1 Advertisement - Members don't see this ad which of the following is the equation for the line that contains the point (3,-1) and is perpendicular to y=3x+3 I know that the slope is -1/3 so I have narrowed it down to these three choices: y=-1/3x+2 y=-1/3x-2 or y=-1/3x thanks so much
Advertisement - Members don't see this ad which of the following is the equation for the line that contains the point (3,-1) and is perpendicular to y=3x+3 I know that the slope is -1/3 so I have narrowed it down to these three choices: y=-1/3x+2 y=-1/3x-2 or y=-1/3x thanks so much
C checkamundo Don't know what i'm doing 10+ Year Member 5+ Year Member 15+ Year Member Joined Jul 11, 2005 Messages 119 Reaction score 0 Points 0 May 25, 2006 #2 henrygl said: which of the following is the equation for the line that contains the point (3,-1) and is perpendicular to y=3x+3 I know that the slope is -1/3 so I have narrowed it down to these three choices: y=-1/3x+2 y=-1/3x-2 or y=-1/3x thanks so much Click to expand... You know that the m= -1/3, then solve for b by plugging in (3,-1) into the eqn: y = mx+b -1 = (-1/3)(3) + b b = 0 so y = (-1/3)x + 0 or y = -1/3x Upvote 0 Downvote
henrygl said: which of the following is the equation for the line that contains the point (3,-1) and is perpendicular to y=3x+3 I know that the slope is -1/3 so I have narrowed it down to these three choices: y=-1/3x+2 y=-1/3x-2 or y=-1/3x thanks so much Click to expand... You know that the m= -1/3, then solve for b by plugging in (3,-1) into the eqn: y = mx+b -1 = (-1/3)(3) + b b = 0 so y = (-1/3)x + 0 or y = -1/3x
