TBR GC EQ example 3.5

[JMMTB]

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At 323 C there are .1 moles H2(g), .2 moles HClO4(g), .1 moles H20(g), and .36 moles HCl(g) at EQ in a 400 ml Flask. What is the Keq for this mixture?

HClO4 + 4 H2 <---> HCl + H2O

A .0362
B .0724
C 1.8
D 44.1


I get .1152


Solution says we can ignore concentration because the number of reactants equals the numbers of products. I understand that volumes would cancel out if the number of reactants did equal the number of products, but I see 5:2 Reactants : Products.

Keq=([H2O][HCl])/([H2]^4)[HClO4])

[HClO4]=(.2/.4)
[H2]=(.1/.4)
[HCl]=(.36/.4)
[H2O]=(.1/.4)

Because H2 is to the fourth power then in reality we need to multiple the answer that TBR says ( C 1.8) by .4^3 giving us .1152

What am I missing?

 

[quicheduty]

Balance your equation!
HClO4 + 4 H2 <---> HCl + 4H2O

 

[JMMTB]

Wow duh overlooked that one. Thanks