The question asks:
If the reaction of X with Y is monitored by visible spectroscopy, then which of the following graphs is expected for the absorbance of light by Reactant X as a function of time? The graphs are labeled with t1, t2 and t3, which represent the elapsed time for the reaction, where t3 > t2 > t1.
I thought since reaction X obeys the zero-order, it should be A but the answer states: "Whether we monitor Reactant X or Reactant Y,the reaction obeys second-order kinetics."
Can anyone explain why this is the case? thx
If the reaction of X with Y is monitored by visible spectroscopy, then which of the following graphs is expected for the absorbance of light by Reactant X as a function of time? The graphs are labeled with t1, t2 and t3, which represent the elapsed time for the reaction, where t3 > t2 > t1.
I thought since reaction X obeys the zero-order, it should be A but the answer states: "Whether we monitor Reactant X or Reactant Y,the reaction obeys second-order kinetics."
Can anyone explain why this is the case? thx
