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TBR GC Book 2 page 46 #88
It's a lot easier to explain if you have the book but here goes:
"In the experiment illustrated by Figure 1, how must the spin rate of the cylinder be adjusted when methane (16 g/mole) is replaced by nitrous oxide (44 g/mole) to get the same results?"
B. It must be slowed by a factor of 1.61. [WRONG]
C. It must be increased by a factor of 1.61. [CORRECT]
As I understand the question, the cylinder originally has methane. Now you are taking out the methane and putting nitrous oxide in it.
TBR's answer explanation seems to think that the situation (unless I am misreading it) is the opposite: the cylinder originally has nitrous oxide but now you have methane.
TBR talks about how since the methane is "faster", the spin rate has to be faster to keep up with the faster methane molecules*. But I thought the question was asking what would happen if NITROUS OXIDE (not methane) is in the chamber? Thus, combining my English reading skills + TBR's conceptual answer, the answer should be B?
*Apart from the English wording issue, I also don't understand the concept TBR is using: Just because methane is faster, why does that mean that the chamber has to spin faster? If the chamber spins slower, the faster methane should be able to enter the chamber even easier.
It's a lot easier to explain if you have the book but here goes:
"In the experiment illustrated by Figure 1, how must the spin rate of the cylinder be adjusted when methane (16 g/mole) is replaced by nitrous oxide (44 g/mole) to get the same results?"
B. It must be slowed by a factor of 1.61. [WRONG]
C. It must be increased by a factor of 1.61. [CORRECT]
As I understand the question, the cylinder originally has methane. Now you are taking out the methane and putting nitrous oxide in it.
TBR's answer explanation seems to think that the situation (unless I am misreading it) is the opposite: the cylinder originally has nitrous oxide but now you have methane.
TBR talks about how since the methane is "faster", the spin rate has to be faster to keep up with the faster methane molecules*. But I thought the question was asking what would happen if NITROUS OXIDE (not methane) is in the chamber? Thus, combining my English reading skills + TBR's conceptual answer, the answer should be B?
*Apart from the English wording issue, I also don't understand the concept TBR is using: Just because methane is faster, why does that mean that the chamber has to spin faster? If the chamber spins slower, the faster methane should be able to enter the chamber even easier.
