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When comparing the second ionization energy of Mg and Na, doesn't the Na have greater second ionization energy due to a GREATER effective nuclear charge that comes from the smaller electronic shell?
My reasoning: I thought it takes more energy to remove the second electron from Na because the second electron is in a full octet, so Na is unwilling to let it go. And since Mg still has its second electron in its 3s2 orbital, it would take a lower energy to remove that electron and stabilize its empty shell, and thus its complete 2p6 octet.
TBR said Mg had the greater second ionization energy. Can someone explain why?
Also, on an unrelated note: I know that across a period, the acidity increases. But to understand the concept, can someone explain to me fundamentally why that is the case?
My reasoning: I thought it takes more energy to remove the second electron from Na because the second electron is in a full octet, so Na is unwilling to let it go. And since Mg still has its second electron in its 3s2 orbital, it would take a lower energy to remove that electron and stabilize its empty shell, and thus its complete 2p6 octet.
TBR said Mg had the greater second ionization energy. Can someone explain why?
Also, on an unrelated note: I know that across a period, the acidity increases. But to understand the concept, can someone explain to me fundamentally why that is the case?