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- Jun 14, 2014
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My algebra's a little rusty, but there's no way this can be right, is there? Subbing random numbers in did not seem to work.
(2h/2g)^1/2 is not (1/2)^2*(2h/g)

(2h/2g)^1/2 is not (1/2)^2*(2h/g)